| (5-óäðîêñè-6-ìåòèëï³ðèäèí-3,4-äè³ë)äèìåòàíîëó ã³äðîõëîðèä
(2-ìåòèë-3-îêñè-4,5-ä³(îêñèìåòèë)-ï³ðèäèíó ã³äðîõëîðèä)
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²äåíòèô³êàö³ÿ.
1 (ÄÔÓ). Òåìïåðàòóðà ïëàâëåííÿ
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2 (ÄÔÓ). Óëüòðàô³îëåòîâèé ñïåêòð ïîãëèíàííÿ
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3 (ÄÔÓ). ²íôðà÷åðâîíèé ñïåêòð ïîãëèíàííÿ
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4 (ÄÔÓ). Òîíêîøàðîâà õðîìàòîãðàô³ÿ
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5 (ÄÔÓ).
↓AgCl + 2NH4OH → [Ag(NH3)2]Cl + 2H2O
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6.
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7.
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8. Ç ðîç÷èíîì àìîí³þ âàíàäàòó â êèñëîò³ ñ³ð÷àí³é êîíö.
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ʳëüê³ñíå âèçíà÷åííÿ.
1 (ÄÔÓ). Àöèäèìåòð³ÿ ó íåâîäíîìó ñåðåäîâèù³
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s = Ò = ––––––––––– ––––––––––––––––––––––––––––––––––––
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2. Àëêàë³ìåòð³ÿ (ïîòåíö³îìåòðè÷íå òèòðóâàííÿ)
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HCl + NaOH → NaCl + H2O
s = Ò = ––––––––––– ––––––––––––––––––––––––––––––––––––
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3. Àëêàë³ìåòð³ÿ
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s = Ò = ––––––––––– ––––––––––––––––––––––––––––––––––––
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4. Àðãåíòîìåòð³ÿ
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s = Ò = ––––––––––– ––––––––––––––––––––––––––––––––––––
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5. Ìåðêóðèìåòð³ÿ
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Na2[Fe(CN)5NO] + Hg(NO3)2 → ¯Hg[Fe(CN)5NO] + 2NaNO3
s = Ò = ––––––––––– ––––––––––––––––––––––––––––––––––––
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Çàñòîñóâàííÿ.
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Ò³àì³íó ã³äðîõëîðèä (Thiamini hydrochloridum) (ÄÔÓ)
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| 3-[(4-àì³íî-2-ìåòèëï³ðèì³äèí-5-³ë)ìåòèë]-5-(2-ã³äðîêñèåòèë)-4-ìåòèëò³àçîë³ëóõëîðèä ã³äðîõëîðèä
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Ò³àì³íó ã³äðîáðîì³ä (Thiamini hydrobromidum) (ÄÔÓ)
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| 3-[(4-àì³íî-2-ìåòèëï³ðèì³äèí-5-³ë)ìåòèë]-5-(2-ã³äðîêñèåòèë)-4-ìåòèëò³àçîë³ëóáðîì³ä ã³äðîáðîì³ä
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²äåíòèô³êàö³ÿ.
1 (ÄÔÓ). ²íôðà÷åðâîíèé ñïåêòð ïîãëèíàííÿ
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2 (ÄÔÓ).
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3 (ÄÔÓ).
↓AgCl + 2NH4OH → [Ag(NH3)2]Cl + 2H2O
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↓AgBr + 2NH4OH → [Ag(NH3)2]Br + 2H2O
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4 (ÄÔÓ).
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5.
Na2S + Na2[Fe(CN)5NO] → Na4[Fe(CN)5NOS]
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ʳëüê³ñíå âèçíà÷åííÿ.
Ò³àì³íó ã³äðîõëîðèä
1 (ªÔ). Àöèäèìåòð³ÿ ó íåâîäíîìó ñåðåäîâèù³
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s = Ò = ––––––––––– ––––––––––––––––––––––––––––––––––––
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2. Àëêàë³ìåòð³ÿ (ïîòåíö³îìåòðè÷íå òèòðóâàííÿ) (ÄÔÓ)
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HCl + NaOH → NaCl + H2O
s = Ò = ––––––––––– ––––––––––––––––––––––––––––––––––––
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Ò³àì³íó ã³äðîáðîì³ä
1 (ÄÔÓ). Àöèäèìåòð³ÿ ó íåâîäíîìó ñåðåäîâèù³
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s = Ò = ––––––––––– ––––––––––––––––––––––––––––––––––––
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2. Àðãåíòîìåòð³ÿ, ïðÿìå òèòðóâàííÿ ï³ñëÿ íåéòðàë³çàö³¿ (ìîäèô³êîâàíèé ìåòîä Ôîëüãàðäà) (äëÿ ³í’ºêö³éíîãî ðîç÷èíó)
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3NH4SCN + FeNH4(SO4)2 → Fe(SCN)3 + 2(NH4)2SO4
3AgNO3 + Fe(SCN)3 → Fe(NO3)3 + 3AgSCN↓
s = Ò = ––––––––––– ––––––––––––––––––––––––––––––––––––
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3. Àëêàë³ìåòð³ÿ
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s = Ò = ––––––––––– ––––––––––––––––––––––––––––––––––––
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4. Àðãåíòîìåòð³ÿ
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s = Ò = ––––––––––– ––––––––––––––––––––––––––––––––––––
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Çàñòîñóâàííÿ.
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