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# A computer that is configured with the IPv6 address as shown in the exhibit is unable to access the internet. What is the problem?

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There should not be an alternative DNS address.
The gateway address is in the wrong subnet.*
The settings were not validated.

15
When subnetting a /64 IPv6 network prefix, which is the preferred new prefix?

/66
/70
/72*
/74

16

2001:DB8:BC15::0
2001:DB8:BC15:A::0*
2001:DB8:BC15:A:1::1
2001:DB8:BC15:A:12::0

17
Which two notations are useable nibble boundaries when subnetting in IPv6? (Choose two.)

/62
/64*
/66
/68*
/70
18
Fill in the blank.
In dotted decimal notation, the IP address ” 172.25.0.126 ” is the last host address for the network 172.25.0.64/26.

The binary representation of the network
where the last six zeros represent the host part of the address.
The last address on that subnet would have the host part equal to 111111,
and the last host address would end in 111110. This results in a binary
representation of the last host of the IP address as 10101100.00011001.00000000.01111110,
which translates in decimal to 172.25.0.126.
19
Fill in the blank.
In dotted decimal notation, the subnet mask ” 255.255.254.0 ” will accommodate 500 hosts per subnet.

If the network has to accommodate 500 hosts per subnet, then we need 9 host bits
(2^9 – 2 = 510 hosts). The Class B subnet mask has 16 bits available and if
we use 9 bits for hosts, we will have 7 network bits remaining.The subnet mask
with 9 host bits is 11111111.11111111.11111110.00000000, which corresponds
to 255.255.254.0.

20
Consider the following range of addresses:
2001:0DB8:BC15:00A0:0000::
2001:0DB8:BC15:00A1:0000::
2001:0DB8:BC15:00A2:0000::

2001:0DB8:BC15:00AF:0000::
The prefix for the range of addresses is “ 60 ”.

All the addresses have the part 2001:0DB8:BC15:00A
in common. Each number or letter in the address
represents 4 bits, so the prefix is /60.
21
Fill in the blank.

A nibble consists of ” 4 ” bits.

A nibble is half of a byte or 4 bits. This is significant because
subnetting in IPv6 is usually done on a nibble boundary.

22
Question as presented:

Place the options in the following order:
- not scored -
192.168.1.64/27
- not scored -
192.168.1.32/27
192.168.1.96/27
23
Question as presented:

Place the options in the following order:
- not scored -
Network C
- not scored -
Network A
Network D
Network B
24
Open the PT Activity.

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